(\partial)/(\partial x)(8y-4x)

Lösung

\frac{\partial}{\partial x} (8 y - 4 x)

- 4

Schritte zur Lösung

\frac{\partial}{\partial x} (8 y - 4 x)

Behandle

y

als Konstante

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (8 y) - \frac{\partial}{\partial x} (4 x)

\frac{\partial}{\partial x} (8 y) = 0

\frac{\partial}{\partial x} (4 x) = 4

= 0 - 4

Vereinfache

= - 4

(3 x)^{^{'}}

y^{^{''}} - 6 y^{^{'}} + 34 y = 0

\frac{\partial}{\partial x} (\frac{1}{3} x^{3})

\int_{- 1}^{2} (7 - 3 t) d t

s l o p e in t erce pt (- 7, - 3), (- 5, - 8)