What is (\partial)/(\partial x)(8y-4x) ?

The answer to (\partial)/(\partial x)(8y-4x) is -4

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(\partial)/(\partial x)(8y-4x)

\frac{\partial}{\partial x} (8 y - 4 x)

- 4

Solution steps

\frac{\partial}{\partial x} (8 y - 4 x)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (8 y) - \frac{\partial}{\partial x} (4 x)

\frac{\partial}{\partial x} (8 y) = 0

\frac{\partial}{\partial x} (4 x) = 4

= 0 - 4

Simplify

= - 4

y^{^{''}} - 6 y^{^{'}} + 34 y = 0

\frac{\partial}{\partial x} (\frac{1}{3} x^{3})

\int_{- 1}^{2} (7 - 3 t) d t

\int csc (d) x d x

What is (\partial)/(\partial x)(8y-4x) ?
The answer to (\partial)/(\partial x)(8y-4x) is -4