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人気のある微分積分 >

2x+3y+(6x+9y-3)y^'=0

解

2 x + 3 y + (6 x + 9 y - 3) y^{^{'}} = 0

解

y = - \frac{2 x}{3} + \frac{W ( \frac{1}{3 e ^{\frac{- 3 x - c _{1}}{3}}} )}{3} + \frac{2}{3}

解答ステップ

2 x + 3 y + (6 x + 9 y - 3) y^{'} (x) = 0

置換を使用して解く:

y = - \frac{2 x}{3} + \frac{W ( \frac{1}{3 e ^{\frac{- 3 x - c _{1}}{3}}} )}{3} + \frac{2}{3}

y = - \frac{2 x}{3} + \frac{W ( \frac{1}{3 e ^{\frac{- 3 x - c _{1}}{3}}} )}{3} + \frac{2}{3}

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