sum from n=0 to infinity of 1/(e^n)

Lösung

n = 0 \sum \infty \frac{1}{e ^{n}}

\frac{e}{e - 1}

Dezimale

1.58197 \dots

Schritte zur Lösung

n = 0 \sum \infty \frac{1}{e ^{n}}

Geometrischen Test der Reihe anwenden:

\frac{e}{e - 1}

= \frac{e}{e - 1}

\frac{d}{d x} (\frac{x + 1}{x + 4})

\frac{\partial}{\partial x} (tan (x^{3} + y^{2}))

x \to 3 + lim (\frac{x + 3}{x - 3})

\frac{\partial}{\partial x} (\frac{x}{x ^{6} - y ^{7}})

n = 4 \sum \infty (x + 1)^{n}