integral of 8x^3+1/x

Lösung

\int 8 x^{3} + \frac{1}{x} d x

2 x^{4} + ln ∣ x ∣ + C

Schritte zur Lösung

\int 8 x^{3} + \frac{1}{x} d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 8 x^{3} d x + \int \frac{1}{x} d x

\int 8 x^{3} d x = 2 x^{4}

\int \frac{1}{x} d x = ln ∣ x ∣

= 2 x^{4} + ln ∣ x ∣

Füge eine Konstante zur Lösung hinzu

= 2 x^{4} + ln ∣ x ∣ + C

\frac{\partial}{\partial y} (e^{7 x e^{y}})

d er i v a t i v e f (x) = 6 x^{3} cot (x)

t an g e n t f (x) = x^{3} 5 - x^{2}, at x = 2

\frac{d}{d x} (- \frac{1}{2} e^{- x^{2}})

\frac{\partial}{\partial x} (x^{3} + sin (3 y))