What is the integral from-2 to 3 of 2/(x^4) ?

The integral from-2 to 3 of 2/(x^4) is diverges

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integral from-2 to 3 of 2/(x^4)

\int_{- 2}^{3} \frac{2}{x ^{4}} d x

diverges

Solution steps

\int_{- 2}^{3} \frac{2}{x ^{4}} d x

Find undefined (singularity) points:

x = 0

If exist

b, a < b < c, f (b) =

undefined

, \int_{a}^{c} f (x) d x = \int_{a}^{b} f (x) d x + \int_{b}^{c} f (x) d x

= \int_{- 2}^{0} \frac{2}{x ^{4}} d x + \int_{0}^{3} \frac{2}{x ^{4}} d x

\int_{- 2}^{0} \frac{2}{x ^{4}} d x =

diverges

If part of the expression diverges, then entire expression diverges

= diverges

\int \frac{2 x + 3}{x ^{2} + 3 x + 3} d x

x \to - 4 lim (x^{2} cos (\frac{5}{x}))

\int \frac{3 tan ( β ) - 4 cos ^{2} ( β )}{cos ( β )} d β

\frac{2 x d y}{d x} = 1 - y^{2}

a re a y = x^{2} - 3, y = 6

What is the integral from-2 to 3 of 2/(x^4) ?
The integral from-2 to 3 of 2/(x^4) is diverges