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Popular Calculus >

y^'=2-(x/(20))

Solution

y^{^{'}} = 2 - (\frac{x}{20})

Solution

y = 2 x - \frac{x ^{2}}{40} + c_{1}

Solution steps

y^{'} (x) = 2 - (\frac{x}{20})

If

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int 2 - \frac{x}{20} d x

\int 2 - \frac{x}{20} d x = 2 x - \frac{x ^{2}}{40} + c_{1}

y = 2 x - \frac{x ^{2}}{40} + c_{1}

Graph

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Frequently Asked Questions (FAQ)

What is the solution for y^'=2-(x/(20)) ?
The solution for y^'=2-(x/(20)) is y=2x-(x^2)/(40)+c_{1}