5y^{''}+15y^'-20y=0

Lösung

5 y^{^{''}} + 15 y^{^{'}} - 20 y = 0

y = c_{1} e^{t} + c_{2} e^{- 4 t}

Schritte zur Lösung

5 y^{''} (t) + 15 y^{'} (t) - 20 y = 0

Solve linear ODE:

y = c_{1} e^{t} + c_{2} e^{- 4 t}

y = c_{1} e^{t} + c_{2} e^{- 4 t}

\int (x^{2} - x + 1) d x

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\int_{0}^{\infty} sin (2 x) d x

x \to 2 lim (\frac{3 x + 1}{x + 2})