xy^'+2y=(3e^{-3x})/x

Lösung

x y^{^{'}} + 2 y = \frac{3 e ^{- 3 x}}{x}

y = - \frac{e ^{- 3 x}}{x ^{2}} + \frac{c _{1}}{x ^{2}}

Schritte zur Lösung

x y^{'} (x) + 2 y = \frac{3 e ^{- 3 x}}{x}

Solve linear ODE:

y = - \frac{e ^{- 3 x}}{x ^{2}} + \frac{c _{1}}{x ^{2}}

y = - \frac{e ^{- 3 x}}{x ^{2}} + \frac{c _{1}}{x ^{2}}

\frac{\partial}{\partial x} (y^{2} - x^{2} - 10)

\frac{t d y}{d t} = t^{3} + 23 t^{3} y

y^{^{''}} - \frac{2 3}{3} y^{^{'}} + \frac{2}{9} = 0

\int_{0}^{2} (2 x - 1)^{2} d x

\int sec (3 t) tan (3 t) d t