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tangent y=6+4x^2-2x^3

解答

切线

y = 6 + 4 x^{2} - 2 x^{3}

解答

y = (- 6 a_{0}^{2} + 8 a_{0}) x + 4 a_{0}^{3} - 4 a_{0}^{2} + 6

求解步骤

计算在一般点

x = a_{0}

的切线

找到切点:

(a_{0}, 6 + 4 a_{0}^{2} - 2 a_{0}^{3})

计算

y = 6 + 4 x^{2} - 2 x^{3}

的斜率:

\frac{d y}{d x} = - 6 x^{2} + 8 x

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 6 a_{0}^{2} + 8 a_{0}

找到斜率 m=

- 6 a_{0}^{2} + 8 a_{0}

且穿过

(a_{0}, 6 + 4 a_{0}^{2} - 2 a_{0}^{3})

的直线:

y = (- 6 a_{0}^{2} + 8 a_{0}) x + 4 a_{0}^{3} - 4 a_{0}^{2} + 6

y = (- 6 a_{0}^{2} + 8 a_{0}) x + 4 a_{0}^{3} - 4 a_{0}^{2} + 6

作图

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