xy^2y^'=x+4

Lösung

x y^{2} y^{^{'}} = x + 4

y = 3 3 x + 12 ln (x) + c_{1}

Schritte zur Lösung

x y^{2} y^{'} (x) = x + 4

Solve separable ODE:

y = 3 3 x + 12 ln (x) + c_{1}

y = 3 3 x + 12 ln (x) + c_{1}

\frac{d}{d x} (3 cot (\frac{x}{8}))

\int z e^{2 z} d z

\int_{0}^{6} x^{3} x^{2} + 36 d x

x \to - 3 - lim (\frac{( x + 2 )}{x + 3})

x (e^{\frac{y}{x}} - 1) y^{^{'}} = e^{\frac{y}{x}} (y - x), y (1) = 0