What is area y=-2sqrt(x),y=2sqrt(x),x=0,x=16 ?

The answer to area y=-2sqrt(x),y=2sqrt(x),x=0,x=16 is 512/3

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area y=-2sqrt(x),y=2sqrt(x),x=0,x=16

area

y = - 2 x, y = 2 x, x = 0, x = 16

\frac{512}{3}

Decimal

170.66666 \dots

Solution steps

Apply the area formula:

\int_{0}^{16} 4 x d x

Solve

\int_{0}^{16} 4 x d x : \frac{512}{3}

The area is:

= \frac{512}{3}

t an g e n t f (x) = 8 x^{2} + 3 x

\frac{\partial}{\partial x} (2 y - \frac{1}{x} + cos (3 x))

\int x^{3} x^{4} + 9 d x

\frac{\partial}{\partial y} (2 x y^{2} - 3)

x \to 1 lim (\frac{x + 4}{x + 2})

What is area y=-2sqrt(x),y=2sqrt(x),x=0,x=16 ?
The answer to area y=-2sqrt(x),y=2sqrt(x),x=0,x=16 is 512/3