What is the derivative of e^xx+e^x ?

The derivative of e^xx+e^x is e^xx+2e^x

What is the first derivative of e^xx+e^x ?

The first derivative of e^xx+e^x is e^xx+2e^x

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\frac{d}{d x} (e^{x} x + e^{x})

e^{x} x + 2 e^{x}

Solution steps

\frac{d}{d x} (e^{x} x + e^{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (e^{x} x) + \frac{d}{d x} (e^{x})

\frac{d}{d x} (e^{x} x) = e^{x} x + e^{x}

\frac{d}{d x} (e^{x}) = e^{x}

= e^{x} x + e^{x} + e^{x}

Simplify

= e^{x} x + 2 e^{x}

x (sin (x))

\frac{d}{d x} (- 1 + 4 sin (x))

\frac{\partial}{\partial x} (2)

\frac{d y}{d x} = \frac{( 3 x ^{2} + 4 x - 4 )}{2 y - 4}

2 tan (θ)

What is the derivative of e^xx+e^x ?
The derivative of e^xx+e^x is e^xx+2e^x
What is the first derivative of e^xx+e^x ?
The first derivative of e^xx+e^x is e^xx+2e^x