integral from-2 to-1 of (-2x+1)

Lösung

\int_{- 2}^{- 1} (- 2 x + 1) d x

4

Schritte zur Lösung

\int_{- 2}^{- 1} - 2 x + 1 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int_{- 2}^{- 1} 2 x d x + \int_{- 2}^{- 1} 1 d x

\int_{- 2}^{- 1} 2 x d x = - 3

\int_{- 2}^{- 1} 1 d x = 1

= - (- 3) + 1

Vereinfache

= 4

\int_{- 1}^{0} π (1 - x^{2})^{2} d x

t an g e n t f (x) = 2 x^{3} - x^{2} + 3, (2, 15)

n = 1 \sum \infty \frac{x ^{n}}{n !}

\int \frac{30}{1 - cos ( 5 x )} d x

\int \frac{x ^{6}}{x ^{14} - 1} d x