What is the solution for derivative of f(x)= 2/(x^2)-5x ?

The solution for derivative of f(x)= 2/(x^2)-5x is f(x)=-2/x-(5x^2)/2+c_{1}

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derivative of f(x)= 2/(x^2)-5x

\frac{d}{d x} f (x) = \frac{2}{x ^{2}} - 5 x

f (x) = - \frac{2}{x} - \frac{5 x ^{2}}{2} + c_{1}

Solution steps

\frac{df}{d x} = \frac{2}{x ^{2}} - 5 x

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

f (x) = \int \frac{2}{x ^{2}} - 5 x d x

\int \frac{2}{x ^{2}} - 5 x d x = - \frac{2}{x} - \frac{5 x ^{2}}{2} + c_{1}

f (x) = - \frac{2}{x} - \frac{5 x ^{2}}{2} + c_{1}

x \to \frac{π}{2} lim (\frac{x}{2})

y = tan^{2} (x), (- \frac{π}{4}, 1)

\frac{\partial}{\partial y} (\frac{8 x}{y})

\frac{s}{s ^{2} - 2 s + 4}

\frac{\partial}{\partial u} (3 sin (v) cos (u))

What is the solution for derivative of f(x)= 2/(x^2)-5x ?
The solution for derivative of f(x)= 2/(x^2)-5x is f(x)=-2/x-(5x^2)/2+c_{1}