integral from 1 to 6 of 2

Lösung

\int_{1}^{6} 2 d x

10

Schritte zur Lösung

\int_{1}^{6} 2 d x

Integral einer Konstanten :

\int a d x = a x

= [2 x]_{1}^{6}

Berechne die Grenzen:

10

= 10

\int \frac{( 16 - 9 x ^{2} ) ^{3}}{x ^{6}} d x

\frac{\partial}{\partial x} (x^{2} cos (x y))

\int x (3 sec^{2} (x) - tan^{2} (x)) d x

\int \frac{x}{x ^{2} + 6 x + 18} d x

in v erse l a pl a ce \frac{s + 1}{s ( s ^{2} + 4 s + 4 )}