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受欢迎的微积分 >

tangent 2x^3+8x^2-5x+9

解答

切线

2 x^{3} + 8 x^{2} - 5 x + 9

解答

y = (6 a_{0}^{2} + 16 a_{0} - 5) x - 4 a_{0}^{3} - 8 a_{0}^{2} + 9

求解步骤

计算在一般点

x = a_{0}

的切线

找到切点:

(a_{0}, 2 a_{0}^{3} + 8 a_{0}^{2} - 5 a_{0} + 9)

计算

y = 2 x^{3} + 8 x^{2} - 5 x + 9

的斜率:

\frac{d y}{d x} = 6 x^{2} + 16 x - 5

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 6 a_{0}^{2} + 16 a_{0} - 5

找到斜率 m=

6 a_{0}^{2} + 16 a_{0} - 5

且穿过

(a_{0}, 2 a_{0}^{3} + 8 a_{0}^{2} - 5 a_{0} + 9)

的直线:

y = (6 a_{0}^{2} + 16 a_{0} - 5) x - 4 a_{0}^{3} - 8 a_{0}^{2} + 9

y = (6 a_{0}^{2} + 16 a_{0} - 5) x - 4 a_{0}^{3} - 8 a_{0}^{2} + 9

作图

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