What is the derivative of (2g(x))/(1+f(x)) ?

The derivative of (2g(x))/(1+f(x)) is (2x)/(1+xf)

What is the first derivative of (2g(x))/(1+f(x)) ?

The first derivative of (2g(x))/(1+f(x)) is (2x)/(1+xf)

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derivative of

\frac{2 g ( x )}{1 + f ( x )}

\frac{2 x}{1 + x f}

Solution steps

\frac{d}{d g} (\frac{2 gx}{1 + f x})

Treat

x, f

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{2 x}{1 + f x} \frac{d g}{d g}

Apply the common derivative:

\frac{d g}{d g} = 1

= \frac{2 x}{1 + f x} \cdot 1

Simplify

= \frac{2 x}{1 + x f}

\frac{d}{d x} (4 x^{2} + \frac{1}{x})

y = \frac{5 + sin ( x )}{5 x + cos ( x )}

f (x) = \frac{1}{4 + 3 x}, (2, \frac{1}{10})

- 4 e^{t}

e^{x} y^{^{'}} = e^{- y} + e^{2 x - y}

What is the derivative of (2g(x))/(1+f(x)) ?
The derivative of (2g(x))/(1+f(x)) is (2x)/(1+xf)
What is the first derivative of (2g(x))/(1+f(x)) ?
The first derivative of (2g(x))/(1+f(x)) is (2x)/(1+xf)