What is the solution for (dy)/(dx)+4x^3y=x^3 ?

The solution for (dy)/(dx)+4x^3y=x^3 is y=(e^{-x^4+c_{1}})/4+1/4

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(dy)/(dx)+4x^3y=x^3

\frac{d y}{d x} + 4 x^{3} y = x^{3}

y = \frac{e ^{- x^{4} + c_{1}}}{4} + \frac{1}{4}

Solution steps

\frac{d y}{d x} + 4 x^{3} y = x^{3}

Solve separable ODE:

y = \frac{e ^{- x^{4} + c_{1}}}{4} + \frac{1}{4}

y = \frac{e ^{- x^{4} + c_{1}}}{4} + \frac{1}{4}

\int \frac{41}{x ^{3} - 125} d x

\int \frac{ln ( 15 x )}{x} d x

\int \frac{x ^{3} + 2 x ^{2} - 4}{x ^{2}} d x

\int \frac{1}{2 x - 2 x} d x

x \to 0 lim (ln (e^{x} - 1))

What is the solution for (dy)/(dx)+4x^3y=x^3 ?
The solution for (dy)/(dx)+4x^3y=x^3 is y=(e^{-x^4+c_{1}})/4+1/4