What is the solution for (dy)/(dx)+(4/x)y=x^4 ?

The solution for (dy)/(dx)+(4/x)y=x^4 is y=(x^5)/9+(c_{1})/(x^4)

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(dy)/(dx)+(4/x)y=x^4

\frac{d y}{d x} + (\frac{4}{x}) y = x^{4}

y = \frac{x ^{5}}{9} + \frac{c _{1}}{x ^{4}}

Solution steps

\frac{d y}{d x} + (\frac{4}{x}) y = x^{4}

Solve linear ODE:

y = \frac{x ^{5}}{9} + \frac{c _{1}}{x ^{4}}

y = \frac{x ^{5}}{9} + \frac{c _{1}}{x ^{4}}

x \to 1 lim (x^{\frac{2}{1 - x}})

\frac{3}{x}, \frac{3}{x ^{2}}, 1, 5

\frac{d}{d x} (\frac{2 x ^{2} - x y + 2 y ^{2}}{x - y})

\int x sin (\frac{1}{5}) x d x

x \to 7.7 lim (8.9 x + 8.8)

What is the solution for (dy)/(dx)+(4/x)y=x^4 ?
The solution for (dy)/(dx)+(4/x)y=x^4 is y=(x^5)/9+(c_{1})/(x^4)