面积-4x^2+6.25x+8,2.5x+7,0

解答

面积

- 4 x^{2} + 6.25 x + 8, 2.5 x + 7, 0

无解

求解步骤

要找到相交点，解

f_{i} (x) = f_{j} (x)

- 4 x^{2} + 6.25 x + 8 = 2.5 x + 7 : x = - \frac{- 15 + 481}{32}, x = \frac{15 + 481}{32}

- 4 x^{2} + 6.25 x + 8 = 0 : x = - \frac{- 25 + 9 33}{32}, x = \frac{25 + 9 33}{32}

2.5 x + 7 = 0 : x = - \frac{14}{5}

曲线没有界限

= 无解

a re a y = 4, 2 x, \frac{( - 3 x + 7 )}{2}

n = 1 \sum \infty (1 + \frac{k}{n})^{n}

x \to - 8 - lim (\frac{- 5 x + 2}{x + 8})

\int 3 x sin (3 x) d x

\int x x^{2} - 16 d x