y^'-ky=0

解答

y^{^{'}} - k y = 0

y = e^{k t + c_{1}}

求解步骤

y^{'} (t) - k y = 0

求解可分离方程:

y = e^{k t + c_{1}}

y = e^{k t + c_{1}}

t an g e n t y = x (9.3)

y^{^{'}} - \frac{y}{x} = 2

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