limit as x approaches infinity+of (log_{6}(x))/(log_{8)(x)}

Lösung

x \to \infty + lim (\frac{lo g _{6} ( x )}{lo g _{8} ( x )})

\frac{3 ln ( 2 )}{ln ( 6 )}

Dezimale

1.16055 \dots

Schritte zur Lösung

x \to \infty lim (\frac{lo g _{6} ( x )}{lo g _{8} ( x )})

Wende das L'Hopital Theorem an

= x \to \infty lim (\frac{\frac{1}{x l n ( 6 )}}{\frac{1}{3 l n ( 2 ) x}})

\frac{\frac{1}{x l n ( 6 )}}{\frac{1}{3 l n ( 2 ) x}} = \frac{3 ln ( 2 )}{ln ( 6 )}

= x \to \infty lim (\frac{3 ln ( 2 )}{ln ( 6 )})

x \to a lim c = c

= \frac{3 ln ( 2 )}{ln ( 6 )}

\frac{d ^{5}}{d x ^{5}} (\frac{1}{x} + cos (2 x))

\frac{d}{d x} (12 x y)

d er i v a t i v e f (x) = \frac{x + x}{x ^{2}}

d er i v a t i v e f (x) = e^{(x^{2} - x)}

\int e^{x} - x e^{x^{2}} d x