x^2y^{''}+2xy^'-6y=x^2-2

解答

x^{2} y^{^{''}} + 2 x y^{^{'}} - 6 y = x^{2} - 2

y = c_{1} x^{2} + \frac{c _{2}}{x ^{3}} + \frac{15 x ^{2} ln ( x ) - 3 x ^{2} + 25}{75}

求解步骤

x^{2} y^{''} (x) + 2 x y^{'} (x) - 6 y = x^{2} - 2

求解线性方程:

y = c_{1} x^{2} + \frac{c _{2}}{x ^{3}} + \frac{15 x ^{2} ln ( x ) - 3 x ^{2} + 25}{75}

y = c_{1} x^{2} + \frac{c _{2}}{x ^{3}} + \frac{15 x ^{2} ln ( x ) - 3 x ^{2} + 25}{75}

\frac{\partial}{\partial x} (d)

\frac{d}{d x} (e^{10})

a re a (x - 1)^{3}, x - 1, 0, 2

f (x) = \frac{2}{2 x + 1}

\frac{\partial}{\partial y} (\frac{1}{x ^{2} + y ^{2}})