f^'(x)=(x^2+3)/(cos(x))

解答

f^{^{'}} (x) = \frac{x ^{2} + 3}{cos ( x )}

f (x) = \int \frac{x ^{2} + 3}{cos ( x )} d x

求解步骤

f^{'} (x) = \frac{x ^{2} + 3}{cos ( x )}

若

f^{^{'}} (x) = g (x)

则

f (x) = \int g (x) d x

f (x) = \int \frac{x ^{2} + 3}{cos ( x )} d x

f (x) = \int \frac{x ^{2} + 3}{cos ( x )} d x

d er i v a t i v e (\frac{10}{3}) t^{2}

d er i v a t i v e f (x) = \frac{1}{6} x^{4} - 6 x^{2} + 1

\frac{d}{d x} (9 x sin (π x))

x \to 1 lim (\frac{x ^{6} - 1}{x - 1})

\int_{0}^{1} \frac{9}{x ^{5}} d x