derivative P(t)=25e^{0.3t}

Lösung

ableitung von

P (t) = 25 e^{0.3 t}

7.5 e^{0.3 t}

Schritte zur Lösung

\frac{d}{d t} (25 e^{0.3 t})

Entferne die Konstante:

(a \cdot f)^{'} = a \cdot f^{'}

= 25 \frac{d}{d t} (e^{0.3 t})

Wende die Kettenregel an:

e^{0.3 t} \frac{d}{d t} (0.3 t)

= e^{0.3 t} \frac{d}{d t} (0.3 t)

\frac{d}{d t} (0.3 t) = 0.3

= 25 e^{0.3 t} \cdot 0.3

Vereinfache

= 7.5 e^{0.3 t}

\frac{\partial ^{2}}{\partial x \partial y} (x arcsin (\frac{y}{x}))

in v erse l a pl a ce \frac{2}{s ^{2} + 2 s + 2}

\int \frac{3}{2} x^{2} - 3 x^{4} d x

d er i v a t i v e - x^{2} + x + a

\frac{d}{d x} (8 x^{5} + 45 x^{4} + 80 x^{3} + 50 x^{2} + 200)