integral from 0 to 1 of x^2+2

解答

\int_{0}^{1} x^{2} + 2 d x

\frac{7}{3}

十进制

2.33333 \dots

求解步骤

\int_{0}^{1} x^{2} + 2 d x

使用积分加法定则:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{1} x^{2} d x + \int_{0}^{1} 2 d x

\int_{0}^{1} x^{2} d x = \frac{1}{3}

\int_{0}^{1} 2 d x = 2

= \frac{1}{3} + 2

化简

\frac{1}{3} + 2 : \frac{7}{3}

= \frac{7}{3}

\int \frac{tan ( \frac{2}{x} )}{x ^{2}} d x

n = 1 \sum \infty \frac{2 n + 1}{7 ^{n}}

\int_{- 1}^{1} tan (x) d x

x \to 1 - lim (- x^{2} + 5 x + a)

\int_{- π}^{π} sin^{2} (x) d x