derivative f(x)=2x-xln|x|

Lösung

ableitung von

f (x) = 2 x - x ln ∣ x ∣

- ln ∣ x ∣ + 1

Schritte zur Lösung

\frac{d}{d x} (2 x - x ln ∣ x ∣)

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x) - \frac{d}{d x} (x ln ∣ x ∣)

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (x ln ∣ x ∣) = ln ∣ x ∣ + 1

= 2 - (ln ∣ x ∣ + 1)

Vereinfache

= - ln ∣ x ∣ + 1

n = 0 \sum \infty \frac{1 ^{n}}{2 n + 1}

\frac{d}{d x} (x^{8} sin (x))

\frac{\partial}{\partial x} (\frac{x ^{4}}{y})

\frac{\partial}{\partial y} (6 + x ln (x y - 5))

\int 3 sin^{3} (x) cos^{7} (x) d x