laplacetransform 1(t-4)

解答

拉普拉斯变换

1 (t - 4)

\frac{1}{s ^{2}} - \frac{4}{s}

求解步骤

L {1 \cdot (t - 4)}

展开

1 (t - 4) : t - 4

= L {t - 4}

利用拉普拉斯变换的线性特性:

对于函数

f (t), g (t)

和常数

a, b : L {a \cdot f (t) + b \cdot g (t)} = a \cdot L {f (t)} + b \cdot L {g (t)}

= L {t} - L {4}

L {t} : \frac{1}{s ^{2}}

L {4} : \frac{4}{s}

= \frac{1}{s ^{2}} - \frac{4}{s}

x \to 0 + lim (sin^{x} (x))

x \to 1 lim (2 x^{2} + x - 1)

\int 3 e^{x} + 7 sec^{2} (x) d x

\frac{d}{d x} (\frac{e ^{x}}{e ^{x} + e ^{y}})

\int \frac{1 - x}{3 x} d x