y^'+2y=2t

Lösung

y^{^{'}} + 2 y = 2 t

y = t - \frac{1}{2} + \frac{c _{1}}{e ^{2 t}}

Schritte zur Lösung

y^{'} (t) + 2 y = 2 t

Solve linear ODE:

y = t - \frac{1}{2} + \frac{c _{1}}{e ^{2 t}}

y = t - \frac{1}{2} + \frac{c _{1}}{e ^{2 t}}

\int 2 x + 7 e^{x} d x

x \to 2 lim (x)

\frac{d}{d x} ((10 x - 2 x^{2}) (16 - 2 x))

y^{^{'}} + 2 x y^{2} = 0

\int \frac{π}{1.2 - 2 x} d x