y'=y^3-y

Lösung

y^{^{'}} = y^{3} - y

y = \frac{1}{- e ^{2 t + c_{1}} + 1}, y = - \frac{1}{- e ^{2 t + c_{1}} + 1}

Schritte zur Lösung

y^{'} (t) = y^{3} - y

Solve Bernoulli ODE:

y = \frac{1}{- e ^{2 t + c_{1}} + 1}, y = - \frac{1}{- e ^{2 t + c_{1}} + 1}

y = \frac{1}{- e ^{2 t + c_{1}} + 1}, y = - \frac{1}{- e ^{2 t + c_{1}} + 1}

\frac{d}{d x} (3 x^{4} + \frac{1}{3 x ^{4}} + \frac{3}{2 x ^{2}})

\int_{- 5}^{- 2} 4 x^{3} d x

\frac{\partial}{\partial x} (5 x^{2} y^{2})

d er i v a t i v e f (x) = 5 cos^{2} (x)

x \to 4 lim (\frac{x + 4}{x - 3})