面积 y=sqrt(x),y=sqrt(8-x),y=0

解答

面积

y = x, y = 8 - x, y = 0

\frac{32}{3}

十进制

10.66666 \dots

求解步骤

要找到相交点，解

f_{i} (x) = f_{j} (x)

x = 8 - x : x = 4

x = 0 : x = 0

8 - x = 0 : x = 8

= \int_{0}^{4} ∣ f_{1} (x) - f_{3} (x) ∣ d x + \int_{4}^{8} ∣ f_{3} (x) - f_{2} (x) ∣ d x

= \int_{0}^{4} x - 0 d x + \int_{4}^{8} 0 - 8 - x d x

\int_{0}^{4} x - 0 d x = \frac{16}{3}

\int_{4}^{8} 0 - 8 - x d x = \frac{16}{3}

= \frac{16}{3} + \frac{16}{3}

化简

= \frac{32}{3}

y^{^{'}} = y^{2} sin (x^{2}), y (- 2) = \frac{1}{3}

x \to 0 lim (g (x) (f (x)))

\int_{0}^{1} \frac{e ^{x}}{x} d x

\frac{d}{d x} (\frac{x ^{2} + 40 x}{5})

a re a f (x) = 2 + x - x^{2}, 0, 3