What is the solution for (dy)/(dx)+1/3 y= 1/3 (1-2x)y^4 ?

The solution for (dy)/(dx)+1/3 y= 1/3 (1-2x)y^4 is y=\sqrt[3]{1/(-2x-1+c_{1)e^x}}

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(dy)/(dx)+1/3 y= 1/3 (1-2x)y^4

\frac{d y}{d x} + \frac{1}{3} y = \frac{1}{3} (1 - 2 x) y^{4}

y = 3 \frac{1}{- 2 x - 1 + c _{1} e ^{x}}

Solution steps

\frac{d y}{d x} + \frac{1}{3} y = \frac{1}{3} (1 - 2 x) y^{4}

Solve Bernoulli ODE:

y = 3 \frac{1}{- 2 x - 1 + c _{1} e ^{x}}

y = 3 \frac{1}{- 2 x - 1 + c _{1} e ^{x}}

x^{4} \frac{d y}{d x} - 2 x^{3} y = 4 x^{6} - 3 x^{2}

\int \frac{1}{x ^{2} - a ^{2}} d x

\frac{d}{d x} (2 cos (x) - 3 sin (x) + 4)

im pl i c i t \frac{d y}{d x}, (x y)^{\frac{1}{2}} = 1 + x^{2} y

y^{^{''}} + 4 y^{^{'}} + 4 y = \frac{ln ( t )}{t} e^{- 2 t}

What is the solution for (dy)/(dx)+1/3 y= 1/3 (1-2x)y^4 ?
The solution for (dy)/(dx)+1/3 y= 1/3 (1-2x)y^4 is y=\sqrt[3]{1/(-2x-1+c_{1)e^x}}