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Beliebt Rechnen >

inverselaplace 5/((s+2)^4)

Lösung

inverse laplace transformation

\frac{5}{( s + 2 ) ^{4}}

Lösung

\frac{5 e ^{- 2 t} t ^{3}}{6}

Schritte zur Lösung

L^{- 1} {\frac{5}{( s + 2 ) ^{4}}}

Wende inverse Transformationsregel an: if

L^{- 1} {F (s)} = f (t)

dann

L^{- 1} {F (s - a)} = e^{a t} f (t)

Für

\frac{5}{( s + 2 ) ^{4}} : a = - 2, F (s) = \frac{5}{s ^{4}}

= e^{- 2 t} L^{- 1} {\frac{5}{s ^{4}}}

L^{- 1} {\frac{5}{s ^{4}}} : \frac{5 t ^{3}}{6}

= \frac{5 e ^{- 2 t} t ^{3}}{6}

Beliebte Beispiele

derivative of a(x+1(x-{r}(x)))

\frac{d}{d x} (a (x + 1) (x - r (x)))

integral of (-2*x^4)/(2*x^3-3*x^2)

\int \frac{- 2 \cdot x ^{4}}{2 \cdot x ^{3} - 3 \cdot x ^{2}} d x

integral of x^2(1-x)^{1/2}

\int x^{2} (1 - x)^{\frac{1}{2}} d x

\frac{d y}{d x} + 6 y = 0

integral from 2 to 3 of x^5

\int_{2}^{3} x^{5} d x