y^{''}-2y+y=t+1,y(0)=0,y^'(0)=0

Lösung

y^{^{''}} - 2 y + y = t + 1, y (0) = 0, y^{^{'}} (0) = 0

y = - t + e^{t} - 1

Schritte zur Lösung

y^{''} (t) - 2 y + y = t + 1

Solve linear ODE:

y = - t + e^{t} - 1

y = - t + e^{t} - 1

f (x) = - \frac{2}{x}

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