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Beliebt Rechnen >

2y^{''}-2y^'+13y=0

Lösung

2 y^{^{''}} - 2 y^{^{'}} + 13 y = 0

Lösung

y = e^{\frac{t}{2}} (c_{1} cos (\frac{5 t}{2}) + c_{2} sin (\frac{5 t}{2}))

Schritte zur Lösung

2 y^{''} (t) - 2 y^{'} (t) + 13 y = 0

Solve linear ODE:

y = e^{\frac{t}{2}} (c_{1} cos (\frac{5 t}{2}) + c_{2} sin (\frac{5 t}{2}))

y = e^{\frac{t}{2}} (c_{1} cos (\frac{5 t}{2}) + c_{2} sin (\frac{5 t}{2}))

Graph

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