What is (\partial)/(\partial x)(3x^2y^3) ?

The answer to (\partial)/(\partial x)(3x^2y^3) is 6xy^3

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(\partial)/(\partial x)(3x^2y^3)

\frac{\partial}{\partial x} (3 x^{2} y^{3})

6 x y^{3}

Solution steps

\frac{\partial}{\partial x} (3 x^{2} y^{3})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 y^{3} \frac{\partial}{\partial x} (x^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 3 y^{3} \cdot 2 x^{2 - 1}

Simplify

= 6 x y^{3}

\int 3 - 4 x d x

\frac{d}{d x} (1 + \frac{2}{x})

n = 1 \sum \infty 5 (0.8)^{n - 1}

y^{^{''}} + 6 y^{^{'}} = 0

\int_{2}^{\infty} y e^{- 3 y} d y

What is (\partial)/(\partial x)(3x^2y^3) ?
The answer to (\partial)/(\partial x)(3x^2y^3) is 6xy^3