What is the sum from k=0 to infinity of sin(k) ?

The sum from k=0 to infinity of sin(k) is diverges

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sum from k=0 to infinity of sin(k)

k = 0 \sum \infty sin (k)

diverges

Solution steps

k = 0 \sum \infty sin (k)

Apply Series Divergence Test:

diverges

= diverges

2^{40}

6 \frac{d y}{d x} = y^{2}

n = 1 \sum \infty ln (\cdot \frac{1}{n})

\frac{d}{d x} (e^{k t a n (5 x)})

\int 2 cos (3 x) d x

What is the sum from k=0 to infinity of sin(k) ?
The sum from k=0 to infinity of sin(k) is diverges