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人気のある微分積分 >

integral of (6x)/((4-3x^2)^4)

解

\int \frac{6 x}{( 4 - 3 x ^{2} ) ^{4}} d x

解

- \frac{1}{3 ( - 4 + 3 x ^{2} ) ^{3}} + C

解答ステップ

\int \frac{6 x}{( 4 - 3 x ^{2} ) ^{4}} d x

定数を除く:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 6 \cdot \int \frac{x}{( 4 - 3 x ^{2} ) ^{4}} d x

因数

4 - 3 x^{2} : - (- 4 + 3 x^{2})

= 6 \cdot \int \frac{x}{( - ( - 4 + 3 x ^{2} ) ) ^{4}} d x

(- (- 4 + 3 x^{2}))^{4} = (- 4 + 3 x^{2})^{4}

= 6 \cdot \int \frac{x}{( - 4 + 3 x ^{2} ) ^{4}} d x

u置換積分法を適用する

= 6 \cdot \int \frac{1}{6 u ^{4}} d u

定数を除く:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 6 \cdot \frac{1}{6} \cdot \int \frac{1}{u ^{4}} d u

べき乗則を適用する

= 6 \cdot \frac{1}{6} (- \frac{1}{3 u ^{3}})

代用を戻す

u = - 4 + 3 x^{2}

= 6 \cdot \frac{1}{6} (- \frac{1}{3 ( - 4 + 3 x ^{2} ) ^{3}})

簡素化

6 \cdot \frac{1}{6} (- \frac{1}{3 ( - 4 + 3 x ^{2} ) ^{3}}) : - \frac{1}{3 ( - 4 + 3 x ^{2} ) ^{3}}

= - \frac{1}{3 ( - 4 + 3 x ^{2} ) ^{3}}

定数を解答に追加する

= - \frac{1}{3 ( - 4 + 3 x ^{2} ) ^{3}} + C

グラフ

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