derivative of 0.75-2xsin(0.1x)

解

\frac{d}{d x} (0.75 - 2 x sin (0.1 x))

- 2 (0.1 x cos (0.1 x) + sin (0.1 x))

解答ステップ

\frac{d}{d x} (0.75 - 2 x sin (0.1 x))

和/差の法則を適用:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (0.75) - \frac{d}{d x} (2 x sin (0.1 x))

\frac{d}{d x} (0.75) = 0

\frac{d}{d x} (2 x sin (0.1 x)) = 2 (sin (0.1 x) + 0.1 x cos (0.1 x))

= 0 - 2 (sin (0.1 x) + 0.1 x cos (0.1 x))

簡素化

= - 2 (0.1 x cos (0.1 x) + sin (0.1 x))