y^{''}=-3y-4y^'

Lösung

y^{^{''}} = - 3 y - 4 y^{^{'}}

y = c_{1} e^{- t} + c_{2} e^{- 3 t}

Schritte zur Lösung

y^{''} (t) = - 3 y - 4 y^{'} (t)

Solve linear ODE:

y = c_{1} e^{- t} + c_{2} e^{- 3 t}

y = c_{1} e^{- t} + c_{2} e^{- 3 t}

\frac{d y}{d x} = e^{- 2 x + 3 y}

\frac{d}{d x} (tan (\frac{π}{2} x))

\int sec^{3} (x) tan^{3} (x) d x

y^{^{'}} + (1 - \frac{1}{x}) y = x^{2}

d er i v a t i v e \frac{3}{x - 2}