What is the derivative of 2x+cot(x) ?

The derivative of 2x+cot(x) is 2-csc^2(x)

What is the first derivative of 2x+cot(x) ?

The first derivative of 2x+cot(x) is 2-csc^2(x)

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\frac{d}{d x} (2 x + cot (x))

2 - csc^{2} (x)

Solution steps

\frac{d}{d x} (2 x + cot (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x) + \frac{d}{d x} (cot (x))

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (cot (x)) = - csc^{2} (x)

= 2 - csc^{2} (x)

3 y^{^{''}} + 2 y = x^{2} e^{- 3 x}

\frac{d}{d x} (\frac{x ^{2}}{x ^{2} + x + 1})

\int \frac{1}{t ^{2} - 4 t + 13} d t

y = ln (1 - x^{2} + 2 x^{4}), at x = 1

x \to 5 lim (6 - x - x^{2})

What is the derivative of 2x+cot(x) ?
The derivative of 2x+cot(x) is 2-csc^2(x)
What is the first derivative of 2x+cot(x) ?
The first derivative of 2x+cot(x) is 2-csc^2(x)