What is the solution for (dy)/(dx)-4y=x^2+9 ?

The solution for (dy)/(dx)-4y=x^2+9 is y=-(x^2)/4-x/8-73/32+c_{1}e^{4x}

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(dy)/(dx)-4y=x^2+9

\frac{d y}{d x} - 4 y = x^{2} + 9

y = - \frac{x ^{2}}{4} - \frac{x}{8} - \frac{73}{32} + c_{1} e^{4 x}

Solution steps

\frac{d y}{d x} - 4 y = x^{2} + 9

Solve linear ODE:

y = - \frac{x ^{2}}{4} - \frac{x}{8} - \frac{73}{32} + c_{1} e^{4 x}

y = - \frac{x ^{2}}{4} - \frac{x}{8} - \frac{73}{32} + c_{1} e^{4 x}

y = 8 x - x^{2} (1.7)

x \to 0 lim (e^{x} + \frac{1}{x})

\frac{d}{d x} (0.8 x^{1.3})

x \to 3 - lim (- x + 5)

t \to 0 lim (cos (2 t) k)

What is the solution for (dy)/(dx)-4y=x^2+9 ?
The solution for (dy)/(dx)-4y=x^2+9 is y=-(x^2)/4-x/8-73/32+c_{1}e^{4x}