laplacetransform e^{4t}cos(2t)

Lösung

laplace transformation

e^{4 t} cos (2 t)

\frac{s - 4}{( s - 4 ) ^{2} + 4}

Schritte zur Lösung

L {e^{4 t} cos (2 t)}

Wende Transformationsregel an: wenn

L {f (t)} = F (s)

dann

L {e^{a t} f (t)} = F (s - a)

Für

e^{4 t} cos (2 t) : f (t) = cos (2 t), a = 4

= L {cos (2 t)} (s - 4)

L {cos (2 t)} : \frac{s}{s ^{2} + 4}

= \frac{( s - 4 )}{( s - 4 ) ^{2} + 4}

= \frac{s - 4}{( s - 4 ) ^{2} + 4}

x \to \frac{3 π}{2} - lim (tan (x))

d er i v a t i v e \frac{x ^{2} + 2 x - 7}{( x + 1 ) ^{2}}

\int (\frac{( ln ( x ) ) ^{2}}{x ^{2}}) d x

n = 0 \sum \infty 3 (\frac{1}{5})^{n}

\frac{\partial}{\partial x} (\frac{z}{x + 4 y})