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Popular >

y^'=e^{-y}(x^2-6)

Solution

y^{^{'}} = e^{- y} (x^{2} - 6)

Solution

y = ln (\frac{x ^{3}}{3} - 6 x + c_{1})

Solution steps

y^{'} (x) = e^{- y} (x^{2} - 6)

Solve separable ODE:

y = ln (\frac{x ^{3}}{3} - 6 x + c_{1})

y = ln (\frac{x ^{3}}{3} - 6 x + c_{1})

Graph

Popular Examples

y^{''}+6y^'+5y=0,y(0)=0,y^'(0)=3

y^{^{''}} + 6 y^{^{'}} + 5 y = 0, y (0) = 0, y^{^{'}} (0) = 3

integral of e^xsqrt(36-e^{2x)}

\int e^{x} 36 - e^{2 x} d x

derivative of (4e^x)/(cos(x))derivative of

\frac{4 e ^{x}}{cos ( x )}

y^{''}-4y^'+13y=2e^x

y^{^{''}} - 4 y^{^{'}} + 13 y = 2 e^{x}

derivative of x^{3/2}log_{2}(sqrt(x+1))

\frac{d}{d x} (x^{\frac{3}{2}} lo g_{2} (x + 1))

Frequently Asked Questions (FAQ)

What is the solution for y^'=e^{-y}(x^2-6) ?
The solution for y^'=e^{-y}(x^2-6) is y=ln((x^3)/3-6x+c_{1})