y^{''}+28y=0

Lösung

y^{^{''}} + 28 y = 0

y = c_{1} cos (27 t) + c_{2} sin (27 t)

Schritte zur Lösung

y^{''} (t) + 28 y = 0

Solve linear ODE:

y = c_{1} cos (27 t) + c_{2} sin (27 t)

y = c_{1} cos (27 t) + c_{2} sin (27 t)

\int \frac{y ^{2}}{8} d y

d er i v a t i v e x sin (\frac{3}{x})

\int e^{16 x^{2}} d x

\int_{- 1}^{x^{2}} (- 2 t + 2) d t

t an g e n t \frac{5}{x}