What is implicit 9x^2+y^2=9 ?

The answer to implicit 9x^2+y^2=9 is (dy}{dx}=-\frac{9x)/y

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implicit 9x^2+y^2=9

implicit derivative

9 x^{2} + y^{2} = 9

\frac{d y}{d x} = - \frac{9 x}{y}

Solution steps

9 x^{2} + y^{2} = 9

Treat

y

y (x)

Differentiate both sides:

18 x + 2 y \frac{d y}{d x} = 0

Isolate

\frac{d y}{d x} : \frac{d y}{d x} = - \frac{9 x}{y}

\frac{d y}{d x} = - \frac{9 x}{y}

\int \frac{2 ^{x} 3 ^{x} 5 ^{x}}{2} d x

\int \frac{x ^{2} - 2}{x ( x + 1 ) ^{3}} d x

\frac{d}{d t} (4 e^{t} \cdot t)

\int_{2}^{7} \frac{x}{x ^{2} + 6 x + 13} d x

\frac{d}{d x} (e^{\frac{x}{4}})

What is implicit 9x^2+y^2=9 ?
The answer to implicit 9x^2+y^2=9 is (dy}{dx}=-\frac{9x)/y