(\partial)/(\partial y)(e^x+yz)

Lösung

\frac{\partial}{\partial y} (e^{x} + yz)

z

Schritte zur Lösung

\frac{\partial}{\partial y} (e^{x} + yz)

Behandle

x, z

als Konstanten

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (e^{x}) + \frac{\partial}{\partial y} (yz)

\frac{\partial}{\partial y} (e^{x}) = 0

\frac{\partial}{\partial y} (yz) = z

= 0 + z

Vereinfache

= z

\int \frac{1}{e ^{z} + e ^{- z}} d z

\frac{d}{d x} ((3 + x - 2 x^{2})^{\frac{1}{4}})

im pl i c i t \frac{d y}{d x}, 4 x^{2} + 9 y^{2} = 36

y^{^{'}} + 2 x y = x e^{- x^{2}}

d er i v a t i v e 3 2690 - 10 x^{2}