What is (\partial)/(\partial x)(2*(y+4)*(x-4)^3) ?

The answer to (\partial)/(\partial x)(2*(y+4)*(x-4)^3) is 6(y+4)(x-4)^2

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(\partial)/(\partial x)(2(y+4)(x-4)^3)

\frac{\partial}{\partial x} (2 \cdot (y + 4) \cdot (x - 4)^{3})

6 (y + 4) (x - 4)^{2}

Solution steps

\frac{\partial}{\partial x} (2 (y + 4) (x - 4)^{3})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 (y + 4) \frac{\partial}{\partial x} ((x - 4)^{3})

Apply the chain rule:

3 (x - 4)^{2} \frac{\partial}{\partial x} (x - 4)

= 3 (x - 4)^{2} \frac{\partial}{\partial x} (x - 4)

\frac{\partial}{\partial x} (x - 4) = 1

= 2 (y + 4) \cdot 3 (x - 4)^{2} \cdot 1

Simplify

= 6 (y + 4) (x - 4)^{2}

x \to - 3 lim (1.2 x + 2.6)

\frac{\partial}{\partial x} (3 x^{4} y^{5} + 6 x^{7} y^{8})

y = \frac{x - 1}{x - 2} + 3

n = 0 \sum \infty e^{\frac{- 3 n}{2}}

\frac{d y}{d x} = 2 x^{6} y^{2}

What is (\partial)/(\partial x)(2*(y+4)*(x-4)^3) ?
The answer to (\partial)/(\partial x)(2*(y+4)*(x-4)^3) is 6(y+4)(x-4)^2