x^2y^'+xy=8

Lösung

x^{2} y^{^{'}} + x y = 8

y = \frac{8 ln ( x )}{x} + \frac{c _{1}}{x}

Schritte zur Lösung

x^{2} y^{'} (x) + x y = 8

Solve linear ODE:

y = \frac{8 ln ( x )}{x} + \frac{c _{1}}{x}

y = \frac{8 ln ( x )}{x} + \frac{c _{1}}{x}

\frac{\partial}{\partial x} (4 x y + 3)

\int x cos (\frac{π x}{2}) d x

\int_{1}^{2} \frac{1}{2 x + 1} d x

\int v (1 - \frac{2}{3} v^{2})^{6} d v

\frac{\partial}{\partial x} (4 y cos (- 6 x))