What is the solution for 8y^'-ty=7 ?

The solution for 8y^'-ty=7 is y=(7sqrt(pi)\erf(t/4))/(4e^{-\frac{t^2){16}}}+c_{1}e^{(t^2)/(16)}

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8y^'-ty=7

8 y^{^{'}} - t y = 7

y = \frac{7 π erf ( \frac{t}{4} )}{4 e ^{- \frac{t ^{2}}{16}}} + c_{1} e^{\frac{t ^{2}}{16}}

Solution steps

8 y^{'} (t) - t y = 7

Solve linear ODE:

y = \frac{7 π erf ( \frac{t}{4} )}{4 e ^{- \frac{t ^{2}}{16}}} + c_{1} e^{\frac{t ^{2}}{16}}

y = \frac{7 π erf ( \frac{t}{4} )}{4 e ^{- \frac{t ^{2}}{16}}} + c_{1} e^{\frac{t ^{2}}{16}}

\int_{0}^{5} π (25 - 25 x^{2}) d x

f (x) = 8 e^{x} cos (x), (0, 8)

\frac{d}{d t} (\frac{t}{t ^{2} + y ^{2}})

x \to 5 lim (3 x^{2} + 5)

\frac{d}{d x} (\frac{2}{3} x^{2})

What is the solution for 8y^'-ty=7 ?
The solution for 8y^'-ty=7 is y=(7sqrt(pi)\erf(t/4))/(4e^{-\frac{t^2){16}}}+c_{1}e^{(t^2)/(16)}